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A beam of 50 A on a 4 cm liquid hydrogen target gives a luminosity of
5.41037 which with a 1.6 msr solid angle means that the expected
yields can be obtained by multiplying the cross sections in Table 1 by
8.6. This would mean 2.4 counts/second or about 8600
counts/hour at the lowest yield point, Ee = 3.362 GeV, and about 2.8 counts/second at the other Q2 = 4.90 GeV2 point.
The cross sections are a factor of 4 or more higher at all of the other
settings.
12/13/2000