Dose Calculation

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Revision as of 20:25, 5 November 2009

Dose (C/cm):

$\frac{\#e}{1cm} \cdot 1.60 \cdot 10^{-19} C/e \cdot gas gain$

$3.6\cdot10^{11}\times1.6\cdot10^{-19}\times2\cdot10^{5} = 0.01~C/cm$

$1.2\cdot10^{11}\times1.6\cdot10^{-19}\times2\cdot10^{5} = 0.004~C/cm$

$1.4\cdot10^{11}\times1.6\cdot10^{-19}\times2\cdot10^{5} = 0.004~C/cm$

$2.9\cdot10^{11}\times1.6\cdot10^{-19}\times2\cdot10^{5} = 0.009~C/cm$

EM background: $40~kHz/straw$ or $267~Hz/cm$

1 year of running (= 1/3 year beam on target) = $1.1\cdot 10^{7}s \times 267 \frac{e}{s\cdot cm} \times 1.60\cdot10^{-19}C/e \times 2\cdot 10^{5} = 9.0 \cdot 10^{-5} C/cm$

Revision as of 20:23, 5 November 2009 Yvhaarle (Talk \| contribs) ← Previous diff		Revision as of 20:25, 5 November 2009 Yvhaarle (Talk \| contribs) Next diff →
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	* 1 year of running (= 1/3 year beam on target) = <math>1.1\cdot 10^{7}s \times 267 \frac{e}{s\cdot cm} \times 1.60\cdot10^{-19}C/e \times 2\cdot 10^{5} = 9.0 \cdot 10^{-5} C/cm</math>		* 1 year of running (= 1/3 year beam on target) = <math>1.1\cdot 10^{7}s \times 267 \frac{e}{s\cdot cm} \times 1.60\cdot10^{-19}C/e \times 2\cdot 10^{5} = 9.0 \cdot 10^{-5} C/cm</math>

-	* Irradiation dose = 44 years of running	+	* Irradiation dose = <math>\geq</math>44 years of running